Optimal. Leaf size=66 \[ -\frac{2 a^2 \cos (c+d x)}{d \sqrt{a \sin (c+d x)+a}}-\frac{2 a^{3/2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{a \sin (c+d x)+a}}\right )}{d} \]
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Rubi [A] time = 0.0978839, antiderivative size = 66, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {2763, 21, 2773, 206} \[ -\frac{2 a^2 \cos (c+d x)}{d \sqrt{a \sin (c+d x)+a}}-\frac{2 a^{3/2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{a \sin (c+d x)+a}}\right )}{d} \]
Antiderivative was successfully verified.
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Rule 2763
Rule 21
Rule 2773
Rule 206
Rubi steps
\begin{align*} \int \csc (c+d x) (a+a \sin (c+d x))^{3/2} \, dx &=-\frac{2 a^2 \cos (c+d x)}{d \sqrt{a+a \sin (c+d x)}}+2 \int \frac{\csc (c+d x) \left (\frac{a^2}{2}+\frac{1}{2} a^2 \sin (c+d x)\right )}{\sqrt{a+a \sin (c+d x)}} \, dx\\ &=-\frac{2 a^2 \cos (c+d x)}{d \sqrt{a+a \sin (c+d x)}}+a \int \csc (c+d x) \sqrt{a+a \sin (c+d x)} \, dx\\ &=-\frac{2 a^2 \cos (c+d x)}{d \sqrt{a+a \sin (c+d x)}}-\frac{\left (2 a^2\right ) \operatorname{Subst}\left (\int \frac{1}{a-x^2} \, dx,x,\frac{a \cos (c+d x)}{\sqrt{a+a \sin (c+d x)}}\right )}{d}\\ &=-\frac{2 a^{3/2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{a+a \sin (c+d x)}}\right )}{d}-\frac{2 a^2 \cos (c+d x)}{d \sqrt{a+a \sin (c+d x)}}\\ \end{align*}
Mathematica [A] time = 0.153641, size = 118, normalized size = 1.79 \[ \frac{(a (\sin (c+d x)+1))^{3/2} \left (2 \sin \left (\frac{1}{2} (c+d x)\right )-2 \cos \left (\frac{1}{2} (c+d x)\right )-\log \left (-\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )+1\right )+\log \left (\sin \left (\frac{1}{2} (c+d x)\right )-\cos \left (\frac{1}{2} (c+d x)\right )+1\right )\right )}{d \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.57, size = 84, normalized size = 1.3 \begin{align*} -2\,{\frac{ \left ( 1+\sin \left ( dx+c \right ) \right ) \sqrt{-a \left ( \sin \left ( dx+c \right ) -1 \right ) }a}{\cos \left ( dx+c \right ) \sqrt{a+a\sin \left ( dx+c \right ) }d} \left ( \sqrt{a-a\sin \left ( dx+c \right ) }+\sqrt{a}{\it Artanh} \left ({\frac{\sqrt{a-a\sin \left ( dx+c \right ) }}{\sqrt{a}}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac{3}{2}} \csc \left (d x + c\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.46189, size = 649, normalized size = 9.83 \begin{align*} \frac{{\left (a \cos \left (d x + c\right ) + a \sin \left (d x + c\right ) + a\right )} \sqrt{a} \log \left (\frac{a \cos \left (d x + c\right )^{3} - 7 \, a \cos \left (d x + c\right )^{2} - 4 \,{\left (\cos \left (d x + c\right )^{2} +{\left (\cos \left (d x + c\right ) + 3\right )} \sin \left (d x + c\right ) - 2 \, \cos \left (d x + c\right ) - 3\right )} \sqrt{a \sin \left (d x + c\right ) + a} \sqrt{a} - 9 \, a \cos \left (d x + c\right ) +{\left (a \cos \left (d x + c\right )^{2} + 8 \, a \cos \left (d x + c\right ) - a\right )} \sin \left (d x + c\right ) - a}{\cos \left (d x + c\right )^{3} + \cos \left (d x + c\right )^{2} +{\left (\cos \left (d x + c\right )^{2} - 1\right )} \sin \left (d x + c\right ) - \cos \left (d x + c\right ) - 1}\right ) - 4 \,{\left (a \cos \left (d x + c\right ) - a \sin \left (d x + c\right ) + a\right )} \sqrt{a \sin \left (d x + c\right ) + a}}{2 \,{\left (d \cos \left (d x + c\right ) + d \sin \left (d x + c\right ) + d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.41523, size = 350, normalized size = 5.3 \begin{align*} \frac{\frac{2 \, a^{2} \arctan \left (-\frac{\sqrt{a} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - \sqrt{a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a}}{\sqrt{-a}}\right ) \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right )}{\sqrt{-a}} - a^{\frac{3}{2}} \log \left ({\left | -\sqrt{a} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + \sqrt{a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a} \right |}\right ) \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right ) - \frac{{\left (2 \, a^{2} \arctan \left (\frac{\sqrt{2} \sqrt{a} + \sqrt{a}}{\sqrt{-a}}\right ) - \sqrt{-a} a^{\frac{3}{2}} \log \left (\sqrt{2} \sqrt{a} + \sqrt{a}\right ) - 2 \, \sqrt{2} \sqrt{-a} a^{\frac{3}{2}}\right )} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right )}{\sqrt{-a}} + \frac{2 \,{\left (a^{2} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right ) \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - a^{2} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1\right )\right )}}{\sqrt{a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a}}}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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